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Latest posts from topic “Circuito RLC, dubbio sulla soluzione di regime.” Latest posts from topic “Circuito RLC, dubbio sulla soluzione di regime.” on “ElectroYou”. 2018-01-06T21:16:04Z https://www.electroyou.it/forum/viewtopic.php?f=2&t=72205 Re: Circuito RLC, dubbio sulla soluzione di regime. https://www.electroyou.it/forum/viewtopic.php?f=2&t=72205#p748727 noisemake 2018-01-08T10:33:07Z 2018-01-08T10:33:07Z
OK grazie mille :)
Re: Circuito RLC, dubbio sulla soluzione di regime. https://www.electroyou.it/forum/viewtopic.php?f=2&t=72205#p748653 RenzoDF 2018-01-07T17:06:51Z 2018-01-07T17:06:51Z
E se si avesse E=0 per t>0 ?

Data per corretta la soluzione data del testo, le tue due ipotesi non sono ammissibili.
Re: Circuito RLC, dubbio sulla soluzione di regime. https://www.electroyou.it/forum/viewtopic.php?f=2&t=72205#p748648 noisemake 2018-01-07T16:32:53Z 2018-01-07T16:32:53Z
Affinché quel risultato sia corretto deve essere la tensione sul condensatore pari a zero.
Ma non solo perché se così fosse non troverei valori corretti di A e B.

Infatti imponendo
[unparseable or potentially dangerous latex formula]
otterrei 0=A+1 quindi A=-1

e che

[unparseable or potentially dangerous latex formula] ottengo
0=\alpha A+ \beta B quindiB=-0,57

ottenendo quindi [unparseable or potentially dangerous latex formula]

Se invece fosse la tensione sul condensatore pari a zero e E=-1V otterrei
[unparseable or potentially dangerous latex formula]

Ma comunque non giungo al risultato.
Re: Circuito RLC, dubbio sulla soluzione di regime. https://www.electroyou.it/forum/viewtopic.php?f=2&t=72205#p748613 RenzoDF 2018-01-07T15:00:57Z 2018-01-07T15:00:57Z
Visto che quel dato E=1 non può che essere interpretato con e(t)=1 V, avrai che all'istante 0+, visto che i(0+)=0 A, la tensione ai morsetti del resistore sarà nulla e così pure la tensione ai morsetti dell'induttore, ne segue (che per l'equazione costitutiva dello stesso) anche la derivata della corrente (vL/L) sarà nulla e quindi la corrente per t>0 rimarrà identicamente nulla e di conseguenza la tensione vC identicamente uguale a 1 volt.

Dalla errata soluzione è comunque facile risalire all'errore nei dati che, una volta corretto, porterà anche la soluzione ufficiale ad essere corretta. ;-)
Re: Circuito RLC, dubbio sulla soluzione di regime. https://www.electroyou.it/forum/viewtopic.php?f=2&t=72205#p748564 noisemake 2018-01-07T11:23:25Z 2018-01-07T11:23:25Z
Potresti spiegarmi meglio RenzoDF?
Re: Circuito RLC, dubbio sulla soluzione di regime. https://www.electroyou.it/forum/viewtopic.php?f=2&t=72205#p748512 RenzoDF 2018-01-07T00:00:05Z 2018-01-07T00:00:05Z
Con le condizioni iniziali indicate, non serve risolvere nessuna equazione differenziale in quanto [unparseable or potentially dangerous latex formula] per t>0.
Circuito RLC, dubbio sulla soluzione di regime. https://www.electroyou.it/forum/viewtopic.php?f=2&t=72205#p748487 noisemake 2018-01-06T21:16:04Z 2018-01-06T21:16:04Z
20180106_203440.jpg

Salve a tutti l'esercizio è un classico circuito RLC .

Non mi è chiaro perché nel risultato non c'è la soluzione particolare cioè quella di regime.

L'equazione differenziale del 2° ordine che mi permette di risolvere l'esercizio è:
[unparseable or potentially dangerous latex formula]


l'omogenea associata è \lambda^2+10^6 \lambda+10^{12}=0

quindi \Delta <0 ed ottengo le due soluzioni \lambda_{1,2}=-10^6/2 \pm \sqrt{3}/2 *10^6 j
\alpha=-5*10^5 e \beta=8,7*10^5

ora l'integrale generale dovrebbe essere
[unparseable or potentially dangerous latex formula]

dove V_{p} è un integrale particolare ,cioè la soluzione di regime per t->\infty ed in tal caso essendo il generatore stazionario otterrei V_{p}=1 .

Ma a questo punto se considero V_{p} non riesco a trovare i valori corretti di A e B.